Answer:
The value is
Explanation:
From the question we are told that
The electric flux is
Generally the net charge is mathematically represented as
Here is the permetivity of free space with value
So
=>
Answer:
Capacitive reactance is 132.6 Ω.
Explanation:
It is given that,
Capacitance,
Voltage source, V = 20 volt
Frequency of source, f = 60 Hz
We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :
So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.
Explanation:
Th electric force between charges is inversely proportional to the square of distance between them. It means,
Initial distance, r₁ = 2 cm
Final distance, r₂ = 0.25 cm
Initial force, F₁ = 1 N
We need to find the electric force between charges if the new separation of 0.25 cm. So,
So, the new force is 64 N if the separation between charges is 64 N.
The answer would be increased number <span />of rod cells.Hope this helps :)