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2 years ago

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4x < 16 or 12x > 144

1 answer:

Leviafan [203]2 years ago

4 0

$4x < 16\ or\ 12x > 144\\\\x < 16:4\ or\ x > 144:12\\\\x < 4\ or\ x > 12\\\\x\in(-\infty;\ 4)\ \cup\ (12;\ \infty)$

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