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The initial value of 100 that doubles over each interval.
without the answer choices, I can only describe it and give you an example of the graph.
I'm assuming the function is 100*(2)^x because if it is as listed it would be a quadratic function with a vertical stretch of 100.
without the answer choices, I can only describe it and give you an example of the graph.
I'm assuming the function is 100*(2)^x because if it is as listed it would be a quadratic function with a vertical stretch of 100.
Answer: see below
<u>Step-by-step explanation:</u>
Write each equation in y = mx + b format where m is the slope and b is the y-intercept.
Left side: -4 ≤ x < -1
If you continue the line through the y-axis it will pass through (0, 4) --> b = 4
The rise over run is -1 over 1 --> m = -1
y = (-1)x + (4) --> y = -x + 4
Right side: -1 < x < 4
The line passes through (0,0) --> b = 0.
The rise over run is -1 over 1 --> m = -1
y = (-1)x + (0) --> y = -x