<h3>You will pay $ 30876800</h3>
We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:
<h3 />
Density of gold = 19298 oz/ft³
Volume of gold = 1 ft³
<h3>Mass of gold =?</h3>
Density = mass /volume
19298 = mass / 1
<h3>Mass of gold = 19298 oz</h3>
Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:
1 oz = $ 1600
Therefore,
19298 oz = 19298 × 1600
19298 oz = $ 30876800
Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800
Learn more: brainly.com/question/15407624
Answer:
Lake and River pollution?
Explanation:
Answer:
28.75211 kj
Explanation:
Given data:
Mass of iron bar = 841 g
Initial temperature = 84°C
Final temperature = 7°C
Heat released = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
specific heat capacity of iron is 0.444 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 7°C - 84°C
ΔT = -77°C
By putting values,
Q = 841 g × 0.444 j/g.°C × -77°C
Q = 28752.11 j
In Kj:
28752.11 j × 1 kJ / 1000 J
28.75211 kj
Is a gas in the greenhouse that absorbs and emits radiation within the thermal infrared range.
There are 19.5 g Na in 71.4 g NaHCO₃
Calculate the <em>molecular mass of NaHCO₃</em>.
1 Na = 1 × 22.99 u = 22.99 u
1 H = 1 × 1.008 u = 1.008 u
1 C = 1 × 12.01 u = 12.01 u
3 O = 3 × 16.00 u = <u>48.00 u
</u>
TOTAL = 84.008 u
So, there are 22.99 g of Na in 84.008 g NaHCO₃.
∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na