Pay attention in class then..
Area of a triangle= 1/2 (b)(h).
Area= 1/2 (11)(7)
Area= 77/2
Area= 38.5
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] /
<span>
<span>
<span>
1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) =
<span>
<span>
<span>
0.96374829001368
Angle A = 15.475
Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span>
<span>
<span>
<span>
154.85
</span></span></span>Finally, calculating the third angle is quite easy
Angle C = 180 - Angle (A) - Angle(B)
Angle C = 180 - 15.475 - 154.85
Angle C = 9.675
Source:
http://www.1728.org/trigtut2.htm
Answer:
y = 
Step-by-step explanation:
Substitute x = - 2 into the equation and solve for y
3(- 2) + 5y = 8, that is
- 6 + 5y = 8 ( add 6 to both sides )
5y = 14 ( divide both sides by 5 )
y =
X= -15
First, we want to combine like terms.
4x-10=20+6x
Subtract 4x from both sides
-10=20+2x
Subtract 20 from both sides
-30=2x
Divide by 2 to isolate the variable
X= -15
