Answer:
See below.
Step-by-step explanation:
The rocket's flight is controlled by its initial velocity and the acceleration due to gravity.
The equation of motion is h(t) = ut + 1.2 g t^2 where u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.
(a) h(t) = 64t - 1/2*32 t^2
h(t) = 64t - 16t^2.
(b) The graph will be a parabola which opens downwards with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).
The y-axis is the height of the rocket and the x-axis gives the time.
Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.
<span>(x + 5 1/2) 0.75= 5/8<span>
Convert 0.75 into a fraction
</span></span><span>(x + 5 1/2) 3/4= 5/8
Use distributive property
3/4x + 5 1/2*3/4 = 5/8
Convert 5 1/2 into improper fraction
3/4x + 11/2*3/4 = 5/8
Multiply
3/4x + 33/8 = 5/8
Subtract 33/8 from both sides
3/4x = 5/8 - 33/8
Subtract the numerators but NOT the denominators
3/4x = -28/8
Divide 3/4 on both sides
x = -28/8 divided by 3/4
Convert the division sign to multiplication while flipping the fraction 3/4 to 4/3
x = -28/8 * 4/3
Multiply
Final Answer: x = -112/24 or -4 16/24 or -4 4/6 or -4 2/3 *All answers are equivalent to each other.</span>
Answer:
5% compounded quarterly equals (1.0125)^4 -1=0.0509453369140625 or 5.09453369140625 % APR
250*(1.0125)^20=$320.51 at the end of 5 years
Step-by-step explanation:
Answer:
Look below
Step-by-step explanation:
In Adam's expression, d represents the original price of the game. 0.75d represents 75% of the original price; this is the amount of the discount, since everything is 75% off. Taking the difference of the original price and the discount, d-0.75d, gives us the total price of the game. In Rena's expression, 0.25 represents 25%. This is because taking 75% off of the price means we still pay 100-75 = 25% of the original price. Multiplying the original price, d, by the 0.25, gives us 25% of the original price; this is the total price.
Answer:
x=πn, n∈Z
Step-by-step explanation:
if sin²2x=1-cos²2x, then
1-cos²2x-2cos2x+2=0; ⇒ cos²2x+2cos2x-3=0; ⇔ (cos2x+3)(cos2x-1)=0;
