Given:
The area of the rectangular garden is 18z+24 sq ft.
To find the possible dimensions of the garden.
Formula
The area of the rectangular garden is
where,
l be the length of the rectangle
b be the width.
Let us take l and b be the length and width of the given rectangular park respectively.
Now,
According to the problem,
or,
We can determine that,
l = 6 and b = 3z+4 or vice versa.
Hence,
The possible length and width of the rectangular garden is 6 and (3z+4) respectively.
Both point (5,12) and (11,12) lie on the horizontal line y=12.
If these two points is a leg of the triangle, the other leg must be perpendicular to the horizontal line, that is, the other leg must be vertical, but passing through either (5,12) or (11,12), i.e. lies on either the vertical line x=5 or x=11.
There is only one point that passes through x=11, i.e. point A(11,4).
Notice that the terms in parentheses on both sides of the equation are added to 4.
(3x + 4) + 4 = (5x - 4) + 4
So we can set the equation as.
3x + 4 = 5x - 4
Subtract 3x on both sides of equation.
4 = 2x - 4
Add 4 on both sides of equation.
8 = 2x
Divide both sides of equation by 2.
4 = x
4 is the only value that satisfies the statement.
Answer:
x = 13
Step-by-step explanation:
The sum of angle measures in a triangle is 180°.
m∠M + m∠L + m∠N = 180°
(4x-4)° + (3x+12)° + (6x+3)° = 180°
13x +11 = 180 . . . . . . collect terms, divide by °
13x = 169 . . . . . . . . . subtract 11
x = 13 . . . . . . . . . . . . . divide by 13
Answer: 12x + 4y
Step-by-step explanation: