Ok, so first convert both the numbers to improper fractions. (Multiply the denominator of the fraction by the whole number and add the numerator of the fraction)
Then keep the first number the same, change the division symbol to a multiplication symbol and use the reciprocal of the second number. (flip the numbers so that the denominator becomes the numerator and the numerator becomes the denominator.)
Then simply multiply across.
Hey there!
One way to do this is find all the factors of 6 and then see which pair fit the requirements.
The factors of 6 are 1, 2, 3, and 6. (Note: There can be negative factors, but I am going to leave them out since it is asking for positive integers.)
You can find them by asking if each number can go into 6.
1, 2, 3, and 6 all go into 6, while 4 and 5 do not.
The requirements we have is that they must be consecutive <u>and</u> have a product of 6.
Consecutive means right after one another.
The only numbers that fit this are 2 and 3.
2 x 3 = 6
Hope this helps!
Thats easy its 7/6 hope this helps
You can test this using the equation: a^2 + b^2 = c^2.
24^2 + b^2 = 60^2
576 + b^2 = 3,600
b^2 = 3,024
b = 54.999
Since b is not a whole number, the side lengths do not form a Pythagorean triple.
Brainliest answer please!!!