You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
A= (a+b/2) × h
Is the formula for a trapezoid
Answer:
its B bro come on
Step-by-step explanation:
ok good
S = 10x^2
S/10 = x^2
+or-sqrt(S/10) = x
+or- sqrt(S10)/10 = x
so
_inverse = +or-sqrt(10x)/10
Answer:
the answer is d
Step-by-step explanation:
i dont really know why but the circle thats not colored in is on -9 and the one that is colored in is on 6 so yeah
