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2 years ago

Describe the vector below shown below as an ordered pair. X-value? Y-value?

Mathematics

2 answers:

Cloud [144]2 years ago

6 0

$\bf \begin{cases}
x=rcos(\theta )\\
y=rsin(\theta )\\
------\\
r=22\\
\theta =39
\end{cases}\implies (\stackrel{x}{22\cdot cos(39^o)}~,~\stackrel{y}{22\cdot sin(39^o)})
\\\\\\
(x,y)\approx (17.09721115~~,~~13.84504860)$

rosijanka [135]2 years ago

3 0

The red vector has a magnitude of 22 and makes an angle of 39 degrees with the horizonal x-axis.

Converting to rectangular form: x = 22 cos 39 deg and y = 22 sin 39 deg

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8 months ago

67. The line contains the point (4,0) and is parallel to the line defined by 3x = 2y.

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$y=\frac{3}{2} x-6$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form:

$y=mx+b$ where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)

Parallel lines will always have the same slope but different y-intercepts.

1) Determine the slope of the parallel line

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

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Now that this equation is in slope-intercept form, we can easily identify that $\frac{3}{2}$ is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope $\frac{3}{2}$ . Plug this into $y=mx+b$ :