Step-by-step explanation:
Right, okay, so this is a bit of a weird one. Let's go step by step.
"Today, 6 friends went out for lunch." = The number 6 is gonna be in our equation somewhere.
"Their total bill was $27.60" = so is the number 27.6
"They decided to split the bill equally" = 27.6 "split equally" (aka divided by) 6 friends is 4.6
"each paid with a $10 bill" = This is where it gets a lil weird. So, if they divided the bill among them, none of their amounts are gonna be anywhere near ten dollars. This is one of those questions that wouldn't really happen in real life. People would probably use fives instead, but whatever. So a number we'll be using for something is 10.
"How much money will each person get back?" = So we have to find the amount they all paid (10) minus the amount each one had to pay (4.6).
To put it all into a full equation...
10 - ( 27.6 / 6 )
Divide.
10 - 4.6
Subtract.
5.4
Put back into money form.
$5.40
Answer:
Each person will get back $5.40.
Answer:
1) 12
2) Yes, there could be 16 people
3) 1/2 of one segment which is 1 block or 2 skinny blocks
4) 1/12
5) 1 of 4 people -> This means that each person gets 1.5/6 pieces which is greater than 0.66/12 piece
1.5/6 = 3/12 which is greater than 0.66/12 piece
Step-by-step explanation:
Answer:
437.4 meters squared
Step-by-step explanation:
7.2*4.5=32.4=b
3*4.5=13.5=h
b*h=a
32.4*13.5=437.4m^2
Answer:
Original claim is 
Opposite claim is 
Null and alternative hypotheses:
Significance level: 0.01
Test statistic:
We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:
Press STAT and the scroll right to TESTS
Scroll down to 2-SampTTest... and scroll to stats.
Enter below information.
Pooled: Yes
Calculate.
The output is in the attachment.
Therefore, the test statistic is:
P-value: 0.4412
Reject or fail to reject: Fail to reject
Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.
