(2n+4)x(4n+7)
= 8n^2+14x+16n+28
=8n^2+30n+28
that's it :) !!
Given:
Consider the below figure attached with this question.
and 
.
To find:
The measure of angle 3.
Solution:
From the below figure it is clear that, angle 3 and angle 4 are vertically opposite angles.
We know that, vertically opposite angles are always equal. So,
Now,
Therefore, the measure of angle 3 is 140 degrees.
Answer:
-30
Step-by-step explanation:
I'm assuming the equation is 
. If it is not please tell me.
If we know the values of m and n, we can just substitute inside the expression.
Hope this helped!
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
Six Squares, the answer is 36.
