Answer:
Kevin could drive 408 miles using 16 miles of gas.
Step-by-step explanation:
357 (1/14) = 25.5
25.5 (16) = 408
Answer:
138.16 in²
Step-by-step explanation:
The surface area SA of the cone is the sum of the base area B and the lateral area LA. The lateral area is half the product of the circumference and the slant height. The radius is half the diameter, so is 4 inches.
SA = B + LA
= πr² + (1/2)(2πrh) . . . . where h is the slant height
= (πr)(r +h)
Filling in the numbers, you have ...
SA = (3.14)(4 in)(4 in + 7 in) = 3.14×(44 in²) = 138.16 in²
<h3>
Answer: B) Median</h3>
The middle vertical line inside the box is the median or the value of Q2. The term "median" is used more often instead of Q2, but your book may use this terminology as well.
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side notes:
* The left and right edges of the box are Q1 and Q3 respectively
* The IQR (interquartile range) is found by subtracting Q3 and Q1
* The min and max are the left and right most edges of the the whiskers, this is assuming there are no outliers
* There is no way to get the mean or mode from a box and whisker plot alone.
* The term "average" is too vague and could refer to mean, median, or mode.
In a 30 - 60 - 90 triangle the side opposite the hypotenuse is 1/2 the hypotenuse and which will be the shorter side. Read this over a couple of times till you realize that (x + 12)/2 is the shortest side.
[(x + 12) / 2]^2 + x^2 = (x + 12)^2 subtract [(x + 12)/2]^2 from both sides.
x^2 = (x +12)^2 - [ (x +12)/2]^2
x^2 = (x + 12)^2 [ 1 - (1/2)^2] You were given this as a question in school? It seems awfully hard.
x^2 = (x + 12)^2 [3/4]
4x^2 = 3*(x^2 + 24x + 144)
4x^2 = 3x^2 + 72x + 432
x^2 - 72x - 432 = 0 This is a quadratic, do you know what they are?
The solution to this comes to x = 77.56
I don't think I made a mistake, but it is sure possible.Check the numbers and my method.
Answer:
Step-by-step explanation:
If there needs to be 4 teachers per 21 students, you would divide the total amount of students by 21 and multiply that answer by 4. SO...:
84 ÷ 21 = 4 groups of 21 students.
4 groups × 4 teachers = 16
*** Answer***
16 TEACHERS
