We know that the line is tangent at the point (2,8)
The derivative of the function at x=2 is
So, the tangent line passes through the point (2,8) and has slope 2. The equation is
This line crosses the x axis where y=0:
Ok so basically.... 15^2= 9^2+ x^2
15*15
225= 81+x
-81. -81
144=x^2
12=X
Im pretty sure it’s right!
I used the formula A^2+B^2=C^2
It moves in a horizontal line. Its 'y value' does not change.
Answer:
The equation of the line is y = 6x - 14
Step-by-step explanation:
To find the equation of this line, start by using the two points with the slope formula to find the slope.
m(slope) = (y2 - y1)/(x2 - x1)
m = (16 - 4)/(5 - 3)
m = 12/2
m = 6
Now that we have the slope, we can use that and either point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 4 = 6(x - 3)
y - 4 = 6x - 18
y = 6x - 14
Answer:
The answers are
1/2 taken away from a number
x decreased by 1/2
1/2 subtracted from a number
Hope this helps you
