First year: the depreciation is (35/100) x 20000 = £7000; now the value of the car is £20000 - £7000 = £13000;
Second year: the depreciation is (35/100) x 13000 = £4550; the current value of the car is £13000 - £4550 = £8450.
Answer:
x = 50
Step-by-step explanation:
10x + 300 = 800
subtract 300 from both sides
10x = 500
divide each side by 10
x = 50
Answer:
Step-by-step explanation:
To get the value of the expressions in list A and list B we will substitute y = 5 in each expression.
List A List B
1). 6 + 6y = 6 + 6(5) = 36 6y - 6 = 6(5) - 6 = 24
2). 6(y - 1) = 6(5 - 1) = 24 6(y + 1) = 6(5 + 1) = 36
3). 6y + 1 = 6(5) + 1 = 31 1 + 6y = 1 + 6(5) = 31
Therefore, (6 + 6y) is equivalent to 6(y + 1)
6(y - 1) is equivalent to (6y - 6)
(6y + 1) is equivalent to (1 + 6y)
-0,666666666666666666666667
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