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Alexeev081 [22]

2 years ago

13

A car battery has a rating of 250 ampere-hours. This rating is one indication of the total charge that the battery can provide t

o a circuit before failing. (a) What is the total charge (in coulombs) that this battery can provide? (b) Determine the maximum current that the battery can provide for 37 minutes.

1 answer:

Serga [27]2 years ago

4 0

Answer:

Total charge provided by the battery could be 900000 C.

Maximum current provided by the battery for 37 minutes could be 405.405 A

Explanation:

Rating= 250 A-h

a. Total charge:

$Rating=Q/t\\Q=Rating.t\\$

Suppose t=1h

$Q=250 A(1h)\\Q=250 A(3600 sec)\\Q= 900000 A.sec$

We konw that $Ampere=\frac{Coulomb}{sec}$ , replacing:

$Q=900000(\frac{Coulomb}{sec})(sec)\\Q=900000 Coulomb$

Total charge provided by the battery could be 900000 C.

b. Maximum current for 37 minutes

$I=\frac{Q}{t} \\I=\frac{900000 C}{37*60 sec}\\I=405.405 A$

Maximum current provided by the battery for 37 minutes could be 405.405 A

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Answer:

The change in temperature, $\Delta T=9.45^{\circ} C$

Explanation:

Given that,

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The relation between degrees Celsius and degrees Fahrenheit is given by :

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A supersonic nozzle is also a convergent–divergent duct, which is fed by a large reservoir at the inlet to the nozzle. In the re

Lady_Fox [76]

Answer:

155.38424 K

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Explanation:

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$T_2$ = Temperature at exit

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For isentropic flow

$\frac{T_2}{T_1}=\frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=T_1\times \frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=00\times \left(\frac{1}{10}\right)^{\frac{1.4-1}{1.4}}\\\Rightarrow T_2=155.38424\ K$

The temperature of the flow at the exit is 155.38424 K

From the ideal equation density is given by

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2 years ago

An object in free fall near the surface of the earth accelerates at a rate of 78979.4 mi/hr What is the rate of acceleration for

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Answer:

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Explanation:

Data provided in the question:

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a) In ft/s

Now,

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and,

1 hour = 3600 seconds

thus,

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or

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