Answer:
Estos elementos se denominan metales de transición, metales pesados, elementos del bloque D, etc.
Explanation:
Aquí, en esta pregunta, queremos saber la razón por la cual hay un espacio de 10 elementos entre el calcio, que es un elemento del grupo dos, y el galio, que es un elemento del grupo 3.
Al observar la tabla periódica, la tabla periódica moderna, notamos un bloque de elementos entre los elementos del grupo 2 y los elementos del grupo 3 en la tabla periódica.
Entonces, ¿por qué se colocan estos elementos entre ambos grupos? Se colocan aquí porque no pertenecen en su totalidad al grupo 2, ni tampoco al grupo 3.
Estos elementos presentan una especie de estados de oxidación variables que son responsables de una amplia variedad de propiedades comunes entre ellos.
Answer: Incomplete/half answer
Explanation:
grams of molar mass of the
substance substance in grams
––––––––––– = –––––––––––––––
moles of the
substance one mol
use this formula to asnwer the question
Complete Question
The complete question is show on the first uploaded image
Answer:
This is shown on the second,third , fourth and fifth image
Explanation:
This is shown on the second,third , fourth and fifth image
As we know that neutralization reaction is a reaction in which base react with acid to form salt and water.
When Potassium Hydroxide reacts with Sulphuric Acid, it forms Potassium Sulphate and Water.
As a result of neutralization reaction, Potassium Sulphate and Water is formed.
2KOH + H2SO4 ----> K2SO4 + 2H2O
Here, K2SO4 is found in aqueous medium in neutralization reaction. It is a neutral salt.
C = 12 g
O = 16 g
H = 1 g
<h3>Further explanation
</h3>
Conservation of mass stated that
<em>In a closed system, the masses before and after the reaction are the same
</em>
we can calculate the mass of each atom in the compound :
O in O₂ :
mass O₂ = 32
mass O = 32 : 2 = 16 g
H in H₂O
mass H₂O = 18
mass 2.H + mass O = 18
mass 2.H + 16 = 18
mass 2.H=2
mass H = 1 g
C in CH₄
mass CH₄ = 16
mass C + mass 4.H = 16
mass C + 4.1=16
mass C = 12 g
or we can use formula :
Mass of a single C :
