<em>Answer:</em>
- The atom consist of three parts, proton, neutron and electrons. The electrons determine that i will combine or beak from other substances.
<em>Explanation:</em>
The atom consist of three parts which are following
The proton and neutron form nucleus of an atom. It is present at center of an atom. They have positive charges, while electrons remained outside the nucleus in particular energy levels or shell around the nucleus.
During combination or breaking of substances ,only arrangements of electrons take place. The valence shell electrons decide whether they have to combine or not, while nucleus remained unchanged during any reactions.
Answer:
a=28600J; b=90.6 J/K; c=402 torr
Explanation:
(a) considering the data given
Vapour pressure P1 =0 at Temperature T1 = 42.43˚C,
Vapour pressure P2 = 273.15 at Temperature T2= 315.58 K)
Using the Clausius-Clapeyron Equation
ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)
In 760/140 = ΔH/8.314 J/mol/K × (1/315.58K -- 1/273.15K)
ΔH vap= +28.6 kJ/mol or 28600J
(b) using the Equation ΔG°=ΔH° - TΔS to solve forΔS.
Since ΔG at boiling point is zero,
ΔS =(ΔH°vap/Τb)
ΔS = 28600 J/315.58 K
= 90.6 J/K
(c) using ln (P2/P1) = (ΔH/R)(1/T2 - 1/T1)
ln P298 K/1 atm = 28600 J/8.314 J/mol/K × (1/298.15K - 1/315.58K)
P298 K = 0.529 atm
= 402 torr
I am pretty sure that the element is Iron (Fe)
Answer:1. ![Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=Rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. The rate constant (k) for the reaction is 
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![rate=k[CHCl_3]^x[Cl_2]^y](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5Ex%5BCl_2%5D%5Ey)
k= rate constant
x = order with respect to 
y = order with respect to 
n = x+y= Total order
1. a) From trial 1: ![0.0035=k[0.010]^x[0.010]^y](https://tex.z-dn.net/?f=0.0035%3Dk%5B0.010%5D%5Ex%5B0.010%5D%5Ey)
(1)
From trial 2: ![0.0069=k[0.020]^x[0.010]^y](https://tex.z-dn.net/?f=0.0069%3Dk%5B0.020%5D%5Ex%5B0.010%5D%5Ey)
(2)
Dividing 2 by 1 :![\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0069%7D%7B0.035%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D%7Bk%5B0.010%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore x=1.
b) From trial 2: (3)
From trial 3: ![0.0098=k[0.020]^x[0.020]^y](https://tex.z-dn.net/?f=0.0098%3Dk%5B0.020%5D%5Ex%5B0.020%5D%5Ey)
(4)
Dividing 4 by 3:![\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0098%7D%7B0.0069%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.020%5D%5Ey%7D%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore 
![rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. to find rate constant using trial 1:
![0.0035=k[0.010]^1[0.010]^\frac{1}{2}](https://tex.z-dn.net/?f=0.0035%3Dk%5B0.010%5D%5E1%5B0.010%5D%5E%5Cfrac%7B1%7D%7B2%7D)
