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2 years ago

An undefined term can alwayssometimesnever be used in a theorem.

Mathematics

1 answer:

Wittaler [7]2 years ago

6 0

The answer is sometimes. Hope that helped!

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Trey evaluated 12/15 + 1/10 and got the answer of 13/25. which statement is true about this answer?

Ganezh [65]

Answer:

Option C. His answer is not correct, because the same can not be less than either attend

Step-by-step explanation:

we have

$\frac{12}{15}+\frac{1}{10} =\frac{13}{25}$

we know that

$\frac{12}{15}=0.8$

$\frac{1}{10}=0.10$

$\frac{13}{25}=0.52$

substitute

$0.80+0.10=0.52$ ----> is not true

therefore

His answer is not correct, because the same can not be less than either attend

6 0

2 years ago

Juans three math quizzes this week took him 1/3?4/6?and1/5 hour to complete. List all the fraction from least to greatest

Alex

Answer:

$\frac{1}{5}$ , $\frac{1}{3}$ , $\frac{4}{6}$ .

Step-by-step explanation:

Given fractions $\frac{1}{3}$ , $\frac{4}{6}$ , $\frac{1}{5}$ .

We need to list them from least to greatest.

In order to arrange them from least to greatest, we need to find the least common denominator of $\frac{1}{3}$ , $\frac{4}{6}$ , $\frac{1}{5}$ .

We have 3, 6 and 5 in denominators.

Least common multiple of 3, 6 and 5 is = 30, because 30 is least number that can be divided by all three number 3, 6 and 5.

Let us covert each denominator as 30.

Multiplying first fraction $\frac{1}{3}$ by 10 in top and bottom, we get

$\frac{1}{3} = \frac{1\times10}{3\times10}=\frac{10}{30}$

Multiplying first fraction $\frac{4}{6}$ by 5 in top and bottom, we get

$\frac{4}{6} = \frac{4\times5}{6\times5}=\frac{20}{30}$

Multiplying first fraction $\frac{1}{5}$ by 6 in top and bottom, we get

$\frac{1}{5} = \frac{1\times6}{5\times6}=\frac{6}{30}.$

Now, we can check $\frac{10}{30}, \frac{20}{30} \ and \ \frac{6}{30}.$

$\frac{6}{30}$ is the smallest, $\frac{10}{30}$ is greater and $\frac{20}{30}$ is the greatest.

Therefore, we can arrange fractions $\frac{6}{30}, \frac{10}{30} \ and \ \frac{20}{30}.$

Writing original fractions in place of equivalent fractions, we can write

$\frac{1}{5}$ , $\frac{1}{3}$ and $\frac{4}{6}$ .

Therefore, the order the amounts of paint from least to greatest is:

$\frac{1}{5}$ , $\frac{1}{3}$ , $\frac{4}{6}$ .

4 0

2 years ago

Help me plz for number 14 a-d

Svetllana [295]

The answer for number A would be 1/3

6 0

2 years ago

2/3(6c+4)-(8c-5) Please explain how to do the problem.

irga5000 [103]

2/3(6c+4)-(8c-5)
1) Get rid of the negative signs
New equation (the ones in bold are the changes): 2/3(6c+4)+(-8c)+(5)
2) Use distributive property for the first part by multiplying 2/3*6c= 4c and 2/3*4= 2 2/3
New equation: 4c+2 2/3+ (-8c) + 5
3) Combine like terms: 4c+(-8c)= -4c and 2 2/3+5= 7 2/3
New and simplified equation: -4c+ 7 2/3

5 0

2 years ago

-9 - (18v - 5) = 2(7v - 16) - 3v

andrezito [222]

Answer:

v = 28/29

Step-by-step explanation:

- 9 - (18v - 5) = 2(7v - 16) - 3v

- 9 - 18v + 5 = 14v - 32 - 3v

- 18v - 14v + 3v = - 32 - 5 + 9

- 29v = - 28

v = -28 / -29

v = 28/29

6 0

2 years ago