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2 years ago

Brainiest if correctly answered in 5m

Chemistry

1 answer:

erastovalidia [21]2 years ago

8 0

I will list them from alkaline with the lowest boiling point and alkaline with the highest.

1. C2H6
2. C9H20
3. C11H24
4. C16H34
5. C20H42
6. C32H66
7. C150H302

I have taken a quiz similar to this before and can assure you this is correct and is primarily because of the number of Carbons and Hydrogens within this. More Carbons and Hydrogens causes Boiling Points to increase because of stronger bonds.

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Calculate the molarity of kcl in the solution if the total volume of the solution is 239 ml.

Akimi4 [234]

When concentration is expressed in molarity, this is equivalent to the number of moles of the solute per liter of solution. We are given with the amount of volume which is 239 mL or 0.239 L. However, there is no known information of the amount of solute. So, I can't give an exact answer. For sample purposes, let's just assume that there is 1 mole of KCl in the solution. The molarity would be:

Molarity = 1 moles/0.239 L = 4.184 M

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It has been suggested that hydrogen gas obtained by the decomposition of water might be a substitute for natural gas (principall

Aleks [24]

Answer:

Hydrogen: -141 kJ/g

Methane: -55kJ/g

The energy released per gram of hydrogen in its combustion is higher than the energy released per gram of methane in its combustion.

Explanation:

According to the law of conservation of the energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.

Qc + Qb = 0

Qc = -Qb [1]

We can calculate the heat absorbed by the bomb calorimeter using the following expression.

Q = C . ΔT

where,

C is the heat capacity

ΔT is the change in the temperature

<h3>Hydrogen</h3>

Qc = -Qb = -C . ΔT = -(11.3 kJ/°C) . (14.3°C) = -162 kJ

The heat released per gram of hydrogen is:

$\frac{-162kJ}{1.15g} =-141 kJ/g$

<h3>Methane</h3>

Qc = -Qb = -C . ΔT = -(11.3 kJ/°C) . (7.3°C) = -82 kJ

The heat released per gram of methane is:

$\frac{-82kJ}{1.50g} =-55kJ/g$

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2 years ago