180-55-39=86
x=86
Hope it helps
In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
Answer:
1) 5.44, 2) 3.9
Step-by-step explanation:
1) a/b + 2b - a^2 when a = 1.4 and b = 0.2
plug in the values:
1.4/0.2 + 2(0.2) - (1.4)^2 = 7 + 0.4 - 1.96 = 5.44
2) a[b-2c]^3 - d/e when a = 2, b = -0.75, c = -1, d = 0, e = -12 5/7 (rewritten to -89/7 = 12.71)
again, plug in the values:
2[-0.75-2(-1)]^3 - 0/12.71 = 2[1.25]^3 - 0 = 2[1.95] = 3.9
5x6=25x5=125 (125) I think it’s correct
Answer:
A. Square for Ape.x
Step-by-step explanation:
