The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:
x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
Answer:
BC = 1.71
Step-by-step explanation:
well to start we have to know the relationship between angles, legs and the hypotenuse in a right triangle
α = 70°
a: adjacent = BC
h: hypotenuse = 5
sin α = o/h
cos α= a/h
tan α = o/a
we see that it has (angle, adjacent, hypotenuse)
we look at which meets those data between the sine, cosine and tangent
is the cosine
cos α = a/h
Now we replace the values and solve
cos 70 = a/5
0.34202 = a/5
0.34202 * 5 = a
1.7101 = a
round to the neares hundredth
a = 1.7101 = 1.71
BC = 1.71
Step-by-step explanation:
The expressions are not properly written
Given
RS = 4x – 9
ST = 19
RT = 8x – 14
Based on the given parameters, the addition postulate below is true
RS+ST = RT
Substitute
4x-9+19 = 8x-14
collect like terms
4x-8x = -14-19+9
-4x = -33+9
-4x = -24
x = -24/-4
x = 6
Get RS:
RS = 4x-9
RS = 4(6)- 9
RS = 24-9
RS = 15
Get RT:
RT = 8x - 14
RT = 8(6)-14
RT = 48-14
RT = 34
<h3>2/5 is your answer. </h3><h3>▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓</h3>
☞ First, 0.40 is the same as 40/100.
But we are not done.
<u>Now, doing this you need to find the GCF (Greatest common factor) of 40, 100.</u>
2 x 2 x 5 = 20.
☞ So our GCF is 20.
Divide both the numerator and the denominator by the GCF.
40 ÷ 20 / 100 ÷ 20.
<h2>Simplify to get ☞ 2/5.</h2><h2>▬▬ι══════════════ι▬▬</h2>
Best of luck on your assignment!
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- Emacathy | Top Answerer ♫♪.ılılıll|̲̅̅●̲̅̅|̲̅̅=̲̅̅|̲̅̅●̲̅̅|llılılı.♫♪
<h2 />
Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
__
x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
_____
<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)