Which mass of urea CO(NH2)2 contain the same mass of nitrogen as 101.1g of potassium nitrate?
1 answer:
M(KNO₃)=101.1 g/mol M(CO(NH₂)₂)=60.1 g/mol m(N)=M(N)m(KNO₃)/M(KNO₃) m(N)=2M(N)m(CO(NH₂)₂)/M(CO(NH₂)₂) 2m(CO(NH₂)₂)/M(CO(NH₂)₂)=m(KNO₃)/M(KNO₃) m(CO(NH₂)₂)=M(CO(NH₂)₂)m(KNO₃)/(2M(KNO₃)) m(CO(NH₂)₂)=60.1*101.1/(2*101.1)=30.05 g
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Answer:
1.5x 10^24
Explanation:
for every 1 mol there are 6.02 x 10^23 molecules
2.5 mol x 6.02 x 10^23
-----------------
1 mol
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