January 10. 360,048.
Explanation:
The Earth and the Moon are two space bodies that have each other as the closest to one another. Both of them have their own gravitational pull, with the one of the Earth being much greater, while the one of the Moon being weaker than it is expected for a body of its size. Nevertheless they influence each other with the gravitational pull, which is most noticeable on Earth.
The gravitational pull between these two space bodies is the greatest when they are the closest to each other, while it is the smallest when they are the furthest from each other. On January 10 the distance between Earth and the Moon is the smallest and it is 360,048 km, so the gravitational pull is the greatest on this date. On December 19 the distance between Earth and the Moon is the greatest and it is 406,276 km, so the gravitational pull is the smallest.
Amino acids are the monomers, or the building blocks that make up all proteins.
Answer:
No
Explanation:
Both A alleles and B alleles are dominant over the O alleles. This means that both parents must have an O allele present to even have a chance of having a child with type O blood. Lets say the mother has type O blood with the father having type AB blood. The possible combination would be: AO, BO, AO, BO. The punnett square should look like this:
A B
O AO BO
O AO BO
Answer:
This observation is True
Explanation:
Membrane integral proteins can function as ion channels during the transport of molecules through the membrane. Moreover, integral proteins can also act as pores for the transport of specific molecules between both sides of the membrane, ion channels that mediate effector signals, signaling transduction mechanisms capable of amplifying cellular responses and hormone receptors.
Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
