Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
Answer: the length of one edge of the square base of the second container is 6 inches.
Step-by-step explanation:
The formula for determining the volume of a rectangular container is expressed as
Volume = length × width × height
Considering the first container,
Length = 12 inches
Width = 8 inches
Height to which the water is filled is 6 inches.
Therefore, volume of water in the container is
12 × 8 × 6 = 576 inches³
Considering the second container,
Height of water = 16 inches
Let L represent the length of the square base. Then the area of the square base is L²
Volume of water would be 16L²
Since the water in the first container was poured into the second container, then
16L² = 576
L² = 576/16 = 36
L = √36
L = 6 inches
Answer:
Bryan Lively Professional Records Browse Bryan's professional profiles below to see current job title, work email address, place of employment and phone number. Showing 11 of 11 Results i think
Answer: b)
Step-by-step explanation:
3^3 is equal to 27 exactly, but it asks for an approximate. 27.55 is near 27 so yea, there ya go ^
Answer:
Step-by-step explanation:
The area of the square garden=
Area of a Square of Side length s 
Therefore:
<u>Perimeter</u>
Perimeter of a Square of Side length s=4s
Therefore, the perimeter of the garden =4*16.34=65.36 ft
Since 65 ft < 65.36 ft
Therefore, if you had 65 ft of fencing, it will not be enough to go around and cover the garden.
