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2 years ago

For her book club Sharon reed for 45 minutes each day write an expression for the number of hours she reads in d days

1 answer:

5 0

So first u would need tto know how many hours are in a day so there are 24 hours in a day so u would do 45x72 cause there are 72 hours in 3 days.

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If a certain number is multiplied by five, the result is the same as twenty-one plus twice the original number. What is the valu

expeople1 [14]

7
7 times 5 = 35
21 + 14 (7*2) = 35

6 0

3 years ago

Read 2 more answers

Tara earns $9 for each dog she walks. She walks 10 dogs an hour. After walking dogs for 4 hours, how much money will Tara have e

solong [7]

Answer: $360

Step-by-step explanation:

In one hour, she makes $9 * 10 dogs = $90.

In 4 hours, we simply multiply that by 4 to get $90 * 4 = $360 total

4 0

2 years ago

Read 2 more answers

Speed compares two values in a ratio. calculate the average speed of karen who travels for 2 hours. karen traveled approximately

Mama L [17]

Speed=distance/time
distance=176km
time=2hr

speed=176km/2hr=88km/1hr

88kmph

5 0

2 years ago

6= 1/2z<br> just saying 1/2 equals one half

Fynjy0 [20]

Answer:

z=12

Step-by-step explanation:

6*2=12

z=12

7 0

2 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

2 years ago