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2 years ago

Jack bought 3 protein bars for a total of $4.26 which equation could be used to find the cost c on dollars of each protein bar

1 answer:

kramer2 years ago

3 0

Answer: (C)

<u>Solution:</u>
Jack bought 3 bars for $4.26 thus the cost of each bar can be defined as:

$c = \frac{4.26}{3}$ ⇒ $3c = 4.26$

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A fireman, 25.7 m away from a burning building, directs a stream of water from a ground level fire hose at an angle of 47.5° abo

aleksley [76]

The coordinates of a particle of water "t" seconds after it leaves the end of the fire hose will be
.. (x, y) = (38.4*cos(47.5°)t, -4.9t^2 +38.4*sin(47.5°)t)

Solving for t, we have
.. t = x/(38.4*cos(47.5°)

For x = 25.7 meters, t is about 0.99065 seconds.
Then y will be
.. -4.9*(0.99065)^2 +38.4*sin(47.5°)*0.99065 = 23.238 . . . . meters

The water will hit the building about 23.24 meters above the height of the hose.

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2 years ago

Solve for y<br> X+y=6 <br> X=4<br> Simplify your answer as much as possible<br> Will give Brainliest

maw [93]

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2 years ago

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The population of a certain town was 10,000 in 1990. The rate of change of the population, measured in people per year, is model

Katena32 [7]

The question is incomplete. The complete question is :

The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?

Solution :

According to the question,

The rate of change of population is given as :

$\frac{dP(t)}{dt}=200e^{0.02t}$ in 1990.

Now integrating,

$\int_0^{20}\frac{dP(t)}{dt}dt=\int_0^{20}200e^{0.02t} \ dt$

$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$

$=10,000[e^{0.4}-1]$

$=10,000[0.49]$

=4900

$\frac{dP(t)}{dt}=200e^{0.02t}$

$\int1.dP(t)=200e^{0.02t}dt$

$P=\frac{200}{0.02}e^{0.02t}$

$P=10,000e^{0.02t}$

$P=P_0e^{kt}$

This is initial population.

k is change in population.

So in 1995,

$P=P_0e^{kt}$

$=10,000e^{0.02(5)}$

$=11051$

In 2000,

$P=10,000e^{0.02(10)}$

$=12,214$

Therefore, the change in the population between 1995 and 2000 = 1,163.

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2 years ago

What is the equation of a line that passes through the points (–3, 4) and (2, 8)?

Mrac [35]

Answer:

$\frac{y - 4}{x - ( - 3)} = \frac{8 - 4}{2 - (- 3)} \\ \frac{y - 4}{x + 3} = \frac{4}{5} \\ 5(y - 4) = 4(x + 3) \\ 5y - 20 = 4x + 12 \\ \boxed{4x - 5y + 32 = 0}$

<h2>4x-5y+32=0 is the right answer.</h2>

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2 years ago

> (889 x 27) + 50 is __

MrRissso [65]

Answer:

50 is more than 27

Step-by-step explanation:

27 comes before 50

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2 years ago