Answer:
a. x = + 2
b. x = + 3
c. x = + 2
d. x = + 3
Explanation:
The oxidation number is a formal charge assigned to an atom present in a molecule or formula unit or ion based on some arbitrary rules.
a.
<u>Hg</u>O
The oxidation number of Hg in HgO is:
x + (-2) = 0
x = +2
b.
<u>Al₄</u>C₃
The oxidation number of Al in Al<u>₄</u>C₃ is:
4x +(3 × -4) = 0
4x - 12 = 0
4x = +12
x = 12/4
x = +3
c. CrF₂
x + ( 2 × - 1) = 0
x - 2 = 0
x = + 2
d. Fe₂S₃
2x + ( 3 × - 2) = 0
2x + (-6) = 0
2x = 6
x = 6/2
x = +3
Electrons and protons, but not neutrons.
The greater amount is the solvent and the lesser amount is the solute.
Hence ethanol(200g) which is the greater amount is the solvent here.
And water (145g) which is lesser is the solute here.
Answer:
8.20 % → Percent yield reaction
Explanation:
To find the percent yield of reaction we apply this:
(Produced yield / Theoretical yield) . 100 = %
Produced yield = 112.9 g
Theoretical yield = 1375.5 g
We replace → (112.9g / 1375.5 g) . 100
8.20 % → Percent yield reaction
Answer:
0.2 mL stock solution, 0.8 solvent, 0.1 mL first solution and 0.9 solvent
Explanation:
The final volume for fist solution is 1 mL and concentration must will be 1/5, then 1 mL/5=0.2 mL. For complete the 1 mL add the missing solvent volume 1 mL-0.2 mL=0.8 mL. For second solution, assuming final volume is 1 mL, and concentration 1/10, then we have 1 mL /10=0.1 mL solution 1/5. Completing volume, 1 mL-0.1 mL= 0.9 mL solvent.