Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner-occupied units had a water supply stoppage.
<h3>What is the probability at x =0?</h3>
P(x=0) = 547000/14770000
P(x=0) = 0.0370
Similarly, we have at x=1
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
x f(x)
0 0.0370
1 0.3393
2 0.4137
3 0.1722
4 0.0378
Total 1
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
To learn more about the probability distribution visit:
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A. 3 times 10^4
90000000 divided by 3000 is 30000 which happens to be equal to 3 times 10^4
If you want to learn how to do this just take your whole number ex: 3 and put 10^6 and you will have 3 followed by 6 zeros. The ^ is just how many zeros will follow your whole number at first.
Well 16x12=192 then subtract it by 8 and 184 rolls were eaten! OMG
Answer:
2(2.82 + 3)
2(5.82)
11.65
Step-by-step explanation:
