The solution to the problem is as follows:
<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
and
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA
Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
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I THINK THE CORRECT ANSWER IS A!!!
Answer: C) as x → -∞, y → 3
as x→ ∞ , y → ∞
<u>Step-by-step explanation:</u>
see graph
Notice that as x approaches negative infinity (goes to the left), the y value approaches the asymptote of y = 3.
And as x approaches positive infinity (goes to the right), the y-value increases without bound so goes to infinity.