Answer:
the answer is c,Yes, because the ratios for each input and output are equivalent.
Step-by-step explanation:
Answer:
The coach can do this in 3,003 ways
Step-by-step explanation:
Here, the coach needs to select a team of 5 from a total of 15 players
Mathematically, the number of ways this can be done is simply 15 C5 ways
Generally, if we are to select a number of r items from n items, this can be done in nCr ways = n!/(n-r)!r!
Applying this to the situation on ground, we have;
15C5 = 15!/(15-5)!5! = 15!/10!5! = 3,003 ways
Answer:
b and d
Step-by-step explanation:
just took the test
The sums range from 2 to 12 of which 6 are even out of 11 possible sums.
There are 4 multiples of 3, two of which are odd.
So the number of even sums is 6 and there are 2 unique or odd multiples of 3.
So there are a total 6+2=8 outcomes we want out of 36 possible outcomes.
The probability is then 8/36 or 2/9
Answer:
The answer for y=2x−2 is x=y/2+1
Step-by-step explanation:
