Answer:
33+12t−21t^2
Step-by-step explanation:
(2t-7)²-(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².
4t^2−28t+49−(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².
4t^2−28t+49−(25t^2−40t+16)
To find the opposite of 25t^2
−40t+16, find the opposite of each term.
4t^2−28t+49−25t^2−40t+16
Combine 4t^2 and −25t^2 to get −21t^2.
−21t^2−28t+49+40t−16
Combine −28t and 40t to get 12t.
−21t^2+12t+49−16
Subtract 16 from 49 to get 33.
−21t^2+12t+33
Swap terms to the left side.
33+12t−21t^2
I hope this helped!
Answer:
to multiply any number by 10, just tag ONE zero on the end. To multiply any number by 100, just tag TWO zeros on the end. To multiply any number by 1,000, just tag THREE zeros on the end. Note especially what happens when the number you multiply already ends in a zero or zeros.
Answer:
2x squared +1 (-)x squared -7 is
a.) x squared +8
Step-by-step explanation:
:)
You cannot solve this. TO solve both variables you need to have two equations. Please insert that equation in and I will solve this problem. :)
Answer:
Help me What did you in msnjxnjxnjcdjjhejxjjxjx
