Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Step-by-step explanation:
1.78 . 1012. 4.55 . 1013
ANS. 1,801.36. ANS. 4,609.15
4609.15 - 1801.36 = 2,80679 kilogram
they are 2,806.79 kilogram aparts
$14.50 because your equation would be 4+1.50(7)=$14.50.
Answer:
I would say that the answer is a. because I would go with the lowest one knowing that if I roll anything other than six, I lose this game is designed for you to nearly lose, so I would go with the lowest choice which is a. since i have a lower chance at winning.
Step-by-step explanation: please mark this brainliest and I will be glad to help anytime.
When you divide by 100 you are essentially moving the decimal of the number two places to the left. In undoing this you would have to move the decimal of the number two places to the right.
28.003 would then turn into 2,800.3
Unfortunately I cannot draw a chart on here but that is the best I can do.
