Answer:
p = 2 ; q = 4
Step-by-step explanation:
Given tbe equation :
3p + 2q = 14 - - - (1)
10p + 6q = 44 - - -(2)
What is p and what is q
This is a simultaneous equation ; using elimination method :
Multiply (1) by 6 and (2) by 2
18p + 12q = 84 - - - - (3)
20p + 12q = 88 - - - (4)
Subtract (3) and (4)
-2p = - 4
p = 4/2
p = 2
Put p = 2 in (1)
3p + 2q = 14
3(2) + 2q = 14
6 + 2q = 14
2q = 14 - 6
2q = 8
q = 8/2
q = 4
p = 2 ; q = 4
Answer: < n <
<u>Step-by-step explanation:</u>
| 3n - 2 | - 2 < 1
<u> +2 </u> <u>+2 </u>
| 3n - 2 | < 3
3n - 2 < 3 and 3n - 2 > -3
<u> +2 </u> <u>+2 </u> <u> +2 </u> <u> +2 </u>
3n < 5 and 3n > -1
n < and n >
< n <
Interval Notation:
Graph: o--------------------o
Answer:
I assume your goal is to rationalize the denominator -
So you need to multiply the denominator by its conjugate.
So we have:
->
gg
Answer:
the answer is c, hope this helps
Answer:
opps type miss
Step-by-step explanation:
miss type