Step-by-step explanation:
In this case we have:
Δx = 3/n
b − a = 3
a = 1
b = 4
So the integral is:
∫₁⁴ √x dx
To evaluate the integral, we write the radical as an exponent.
∫₁⁴ x^½ dx
= ⅔ x^³/₂ + C |₁⁴
= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)
= ⅔ (8) + C − ⅔ − C
= 14/3
If ∫₁⁴ f(x) dx = e⁴ − e, then:
∫₁⁴ (2f(x) − 1) dx
= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx
= 2 (e⁴ − e) − (x + C) |₁⁴
= 2e⁴ − 2e − 3
∫ sec²(x/k) dx
k ∫ 1/k sec²(x/k) dx
k tan(x/k) + C
Evaluating between x=0 and x=π/2:
k tan(π/(2k)) + C − (k tan(0) + C)
k tan(π/(2k))
Setting this equal to k:
k tan(π/(2k)) = k
tan(π/(2k)) = 1
π/(2k) = π/4
1/(2k) = 1/4
2k = 4
k = 2
BC = 18
AB = AC, hence
8x - 4 = 5x + 11 ( subtract 5x from both sides )
3x - 4 = 11 ( add 4 to both sides )
3x = 15 ( divide both sides by 3 )
x = 5
BC = 4x - 2 = (4 × 5 ) - 2 = 20 - 2 = 18
45m 6m^5 usually helps to list the factors of each number first,
1x45=453x15=455x9=45
1x6=62x3=6
so the biggest number that fits into both would be 3, and the biggest amount you can take of any variable would be the amount of that lowest variable. when given an "m" and "m^5", you can only take out one "m", because when m÷m=1, that means you can't take any more "m's" out. if it were m^2 and m^5 you would take out m^2 :)
so your final answer would be"3m" and if you were taking it out of an equation (if you had 45m+/-6m^6)would look like 3m(15+/-2m^4
Answer:
um OK
Step-by-step explanation:
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