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mash [69]
2 years ago
11

How do i know which equation to use for dimensional analysis?

Physics
1 answer:
nikitadnepr [17]2 years ago
7 0
You look at the units you want, then try to figure out which units ti multiply by to get the units you have to match the units you want. For example, if you want kg/m^3 and have m/s

You can see that you have a length/time(lets denote it d/t for distance over time) and want mass/volume (lets denote it m/d^3). d/t multiplied by time=d but we want m/d^3 so lets multiply our original d/t by time(t) and mass(m) so d/t(t) (m) =dm. However, we want m/d^3 so we will also have to divide by d^4.

(d/t)(t)(m) /(d^4)=m/d^3 = mass/length^3 =mass/volume which was what we wanted our end result to be.


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Explain what is the capacity of a battery in your own words​
Vinil7 [7]

Battery capacity (AH) is defined as a product of the current that is drawn from the battery while the battery is able to supply the load until its voltage is dropped to lower than a certain value for each cell.

4 0
2 years ago
Identify the y-intercept.
Dmitry [639]

Answer:

1 is the y intercept

Explanation:

the y intercept is where the line crosses the y axis

5 0
2 years ago
Read 2 more answers
Suppose you are holding a container of gas, and the container has a fixed volume (i.e. it won't stretch or give to allow for exp
USPshnik [31]

Answer: if the pressure in the container is doubled, then the temperature will double too.


Justification:


You can rely on Gay-Lussac's law for ideal gases to answer the question.


According to that law, the pressure and temperature of a fixed amount of gas in a closed rigid container (constant volume) varie in direct proportion.


Mathematically, you can write in this way:


P/T = k


P₁ / T₁ = P₂ / T₂


That means, that if the pressure in the container is doubled, then the temperature will double too.


You can see that mathematically:


P₂ = 2 P₁


T₂ = (T₁ / P₁)(P₂) = (T₁ / P₁) (2 P₁) = 2 T₁

6 0
2 years ago
Read 2 more answers
A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling
ivann1987 [24]

Answer:

42.99°

Explanation:

F_h = Kinetic friction force

F_{\theta} = Pulling force at angle \theta

N_h = Weight of the box = 150 N

Kinetic friction force

F_h=\muN_h

Pulling force at angle \theta

F_{\theta}=\muN_{\theta}

N = Pulling force

According to question

\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N

Applying Newton's second law in the vertical direction we get

N_h-Nsin\theta=N_{\theta}\\\Rightarrow 150-110sin\theta=75\\\Rightarrow \theta=sin^{-1}\frac{75}{110}\\\Rightarrow \theta=42.99\ ^{\circ}

The angle is 42.99°

8 0
2 years ago
The driver of a car traveling at 17.7 m/s ap-
FrozenT [24]

Answer:

43 revolutions.

Explanation:

The time it takes for the car to stop is

t=v_i/a=\frac{17.7m/s}{1.38m/s^2}=12.83s

The distance it travels in that time is

d=\frac{1}{2}at^2=\frac{1}{2}(1.38)(12.83) ^2=113.5m

The number of revolutions that the tires make is then

n=\frac{d}{2\pi r} =\frac{113.5}{2\pi *0.42} =\boxed{43\:revolutions}

<em>The last calculation just asks the question "how many tire circumferences fit into d=113 meters?"</em>

5 0
2 years ago
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