Answer:
Option C is the answer.
Step-by-step explanation:
The possible advantage of offering rewards or incentives to increase response rates is :
A possible advantage of offering rewards or incentives to increase response rates is that respondents put more effort into completely and accurately answering the survey questions because they feel obligated.
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The disadvantage can be a biased result or outcome.
Because suppose if it is a product based survey and you are offered some reward for answering the questions, then it is possible that respondents answers are product driven, to get the reward.
The percentile rank for 10 will be 10th.
<h3>What is percentile rank?</h3>
The percentile rank of a particular score in statistics refers to the percentage of scores in the frequency distribution that are smaller than that score.
Percentile rank = [(Number of values below x) + 0.5]/ total number of values * 100
For 10,
Percentile rank = {[0 + 0.5]/5} x 100 = 10th
For 15,
Percentile rank = ([1 + 0.5]/5) x 100 = 30st
For 19,
Percentile rank = [2 + 0.5]/5 x 100 = 50th
For 23,
Percentile rank = [3 + 0.5]/5 x 100 = 70th
For 30,
Percentile rank = [4 + 0.5]/ 5 x 100 = 90th
The percentile rank for 10 will be 10th.
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Answer:
Neither
Step-by-step explanation:
We need to transform one of the equations into its slope-intercept form:
y + 2/5x = 8
Subtract 2/5x from both sides:
y = -2/5x + 8
y = -5/2x - 7
Graphing both lines, they do intersect at point (-7.14, 10.86), but they are not parallel, nor are they perpendicular from each other. By definition, perpendicular lines must appear to be perpendicular (that is, they intersect at a 90° angle).
Looking at the attached graph (where the purple line is y = -2/5x + 8), their lines do not form a 90° angle.
Therefore, the correct answer is neither.
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Below is the solution, I hope it helps.
<span>i) tan(70) - tan(50) = tan(60 + 10) - tan(60 - 10)
= {tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to:
= 8*tan(10)/{1 - 3*tan²(10)}
iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10)
= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)}
= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)}
= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)}
= 3*tan(30) = 3*(1/√3) = √3 [Proved]
[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)},
{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
