Figure 3 shows a stationary metal block hanging from the middle of a stretched wire which is suspended from a horizontal beam. T
he tension in each half of the wire is 15 N. (a) Calculate for the wire at A, (i) the resultant horizontal component of the tension forces, (ii) the resultant vertical component of the tension forces. Can someone explain why the first one is 0?
1 answer:
Explanation:
(i) The horizontal component of the tension in the right wire points right, and the horizontal component of the tension in the left wire points left. Since these components are equal and opposite, the resultant horizontal force is 0.
∑Fₓ = 15 N cos 20° − 15 N cos 20°
∑Fₓ = 0 N
(ii) ∑Fᵧ = 15 N sin 20° + 15 N sin 20°
∑Fᵧ = 10.26 N
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Explanation:
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M = 86 kg
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F = 780 N
also we know that acceleration of the losing player is given as
now by Newton's 2nd law we will have