Answer: B ≈ Credit unions are owned by stockholders rather than partners
Answer:
A 1.5 metres per second squared B 0 C 6 0.5
b) 9m
Explanation:
a= v-a/t
a= acceleration measured in metres per second squared
v= final speed measured in metres per second
u= initial speed measured in metres per second
t= time measured in second
A
a=v-a/t
a= 3-0/2
a= 1.5 metres per second squared
Distance in a velocity time graph = area under
To calculate the distance in the first 4 seconds
You divide the graph into triangles and rectangles
Area A (triangle )= 1/2 × base × height
=1÷2 ×2×3
= 3m
Area B (rectangle)= L×B
=2×3
=6m
Area A + Area B= 3+6
= 9m
The acceleration is given by:
a = v²/r
a = 10²/5
a = 20 m/s²
This is not a realistic value for a runner because it is very large.
No it is not balanced because there are four oxygen atoms in H2SO4 while there 5 oxygen atoms in the reactants side. There are also more hydrogen atoms on the reactants side. To make it balanced remove the 2 in front of H2O. :)
Answer:
The rider experiences weight or does not experience weight depends upon the direction of the elevator in which it moves and its acceleration.
Explanation:
Consider the mass of a rider as m. So its actual weight is mg and it acts vertically downward. The apparent weight of the rider is depended on the acceleration of the elevator and its direction of movement.
When elevator moves with a constant speed i.e. its acceleration is zero, the apparent weight of the rider is equal to the actual weight. Thus the rider's sensation is normal.
If the elevator is moving upward with an acceleration a, then the apparent weight of the rider will be more and the rider will experience an increase in weight or the sensation is heavy.
Or when the elevator moves downward with an acceleration a, the apparent weight of the rider is less. And the rider sensation is lighter.
