11m/s Bc of the fact that he sees her running at 11m/s
Answer:
The time for the cake to cool off to room temperature is
approximately 30 minutes.
Let = F be the temperature and T that of the body
Explanation:
Our Tm = 70, the initial-value problem is
= <em>k</em>(T − 70), T(0) = 300
Solving the equation, we get
= <em>kdt</em>
In [T-70]= <em>kt </em>+
T = 70 +
Finding he value for using the initial value of T (0)= 300, therefore we get:
300=70+
= 230 therefore
T= 70+ 230
Finding the value for <em>k </em>using T (3) = 200, therefore we get
T (3) = 200
=
<em>K </em>= in
= -0.19018
Therefore
T(t) = 70+230
N2 = 3*n1
T2 = 2*T1
V1 = V2
(n2 * T2)/P2 = (n1 * T1)/P1
3 n1 * 2 T1 / P2 = n1 *T1 / P1
P2 = 6*P1
Since P2 is 6P1, it is 6 times greater than original pressure