<h3>Given:</h3>
Fifteen more than z times 6 is 11 less than y times 2
<h3>Solution:</h3>
Fifteen more than z times 6 = 6z + 15
11 less than y times 2 = 2y - 11
<h2>Answer:</h2>
6z + 15 = 2y - 11
We can set up the width a X and, from the description the length would be 3X-1. The perimeter of a rectangle is determined by 2XL + 2Xw. Plugging into the equation 2(3X-1) + 2(X) = 118. Next distribute to get 6X-2 + 2X = 118. Combine like terms to get 8X = 120. Divide by 8 to get X = 15. The width is 15. The length is 3(15)-1 or 44. 88 +30 = 118
Answer:
-15
Step-by-step explanation:
Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)
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The attached graph shows the equivalence of the polar and rectangular forms.
Answer:
(1,3) should be the answer due to the fact that both lines intersect at that point.
Step-by-step explanation: