If x2 + y2 = 14 and xy=5, find the value of (½x+½y)². pls help
2 answers:
Answer:
(½x+½y)²=6
Step-by-step explanation:
x^2 + y^2 = 14, xy=5
(A+B)^2=A^2 +2AB+B^2... (*)
(1/2x+1/2y)^2 =(*)
(1/2x)^2 +2(1/2x)(1/2y)+(1/2y)^2 =
1/4x^2 +1/2xy+1/4y^2=
1/4(x^2 +y^2) +1/2(xy)=
1/4*14+1/2*5=
14/4+5/2=
14/4+10/4=
24/4=6
Answer:
Step-by-step explanation:
Given: x² + y² = 14 and xy = 5
(a + b)² = a² + b² + 2ab
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