A sample of carbon 12 has a mass. Of 6.00g how many atoms of carbon 12 are in the sample

1 answer:

7 0

The number of atoms = number of moles x Avogadro’s number (6.022x10^23)

So first you need to find the number of moles of carbon 12

Number of moles = mass (g)/ molar mass

n= 6/12
= 0.5

Then put that into the equation for number of atoms so
Number of atoms = 0.5 x 6.022 x 10^23
= 3.011x10^23

I’m not 100% sure if that’s correct though

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Draw the alkene formed when 1-heptyne is treated with hbr in the presence of peroxide.

Nimfa-mama [501]

<h2>Heptene formed is -</h2><h2> $CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$ </h2>

Explanation:

The two possibilities when the peroxide is not present

$CH_{3}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-C$ ≡ $CH +HBr$ → $CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_{2}$

$CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_2$ + HBr → $CH_3-CH_2-CH_2-CH_2-CH_2-CBr_2-CH_3$

In presence peroxide,

$CH_3-CH_2-CH_2-CH_2-CH_2-C$ ≡ $CH$ + HBr → $CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$

When peroxides are present in the reaction mixture, hydrogen bromide adds to the triple bond of heptane with regioselectivity.

This reaction is opposite to that of Markovnikov's rule which says that when asymmetrical alkene reacts with a protic acid HX, then the hydrogen of an acid is attached to the carbon with more in number of hydrogen substituents, and the halide (X) group is attached to the carbon with more in number of substituents of alkyl.
One mole of HBr adds to one mole of 1-heptane.
The structure of heptene formed is -

$CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr$

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2 years ago

Look at the rock sitting on the hill in the picture above. Gravity should make the rock slide down the hill. What force is actin

nexus9112 [7]

I believe the answer you are looking for is Static Friction. Static Friction is the force that holds an object in place until it starts to move. Then it switches to rolling friction.

For example, if you have a 1/2 ton truck sitting in front of you and the truck is in neutral. (meaning it can roll if pushed). The truck is extremely hard to move at first. That is because static friction is holding it in place until the amount of force exceeds the limit of static friction.

So if we continue to push at the truck and you feel it starting to move, then once it starts moving it is much easier to push, that is because we moved past static friction to rolling friction. Rolling friction is what helps slow things down. If you roll a ball across a carpet floor it eventually comes to a stop.

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2 years ago

Read 2 more answers

Which of the following is an oxidation-reduction reaction?

Alina [70]

Answer:

last choice

Explanation:

oxidation and reduction can be defined in terms of adding or removing oxygen to a compound

oxidation is gaining oxygen

reduction is to loss oxygen

5 0