This problem mean you have to find the point that the Domain and Range is suit (I'm sorry English is my second language)
Example:
1) G ; 2) Y
If you want me to do the rest of it tell me Okay ^^
Answer: Square
Step-by-step explanation:
A cross section cut parallel to a base will be the same shape as the base itself, and the base of a cube is a square. :)
Area of the figure = 806.5 in²
Solution:
Length of the rectangle = 16 in
Breadth of the rectangle = 9 in
Area of the rectangle = length × breadth
= 16 × 9
Area of the rectangle = 144 in²
Base of the triangle = 31 in
Height of the triangle = 20 in
Area of the triangle =
Area of the triangle = 310 in²
Parallel sides of the trapezium = 16 in and 31 in
Height of the trapezium = 35 – 20 = 15 in
Area of the trapezium =
Area of the trapezium = 352.5 in²
Area of the figure = Area of rectangle + Area of triangle + Area of trapezium
= 144 in² + 310 in² + 352.5 in²
Area of the figure = 806.5 in²
Answer:
Step-by-step explanation:
∠A = arctan(33/43) ≈ 37.5°
AB = √(43² + 33²) = √2938
Law of Sines
∠C = arcsin(sinA ⋅ AB/BC) ≈ 34.7°
supplementary angles = 180 degrees
so x = angle 1
y = angle 2
y = 3x-12
x + 3x-12 =180
4x-12 = 180
4x = 192
x = 192/4 = 48
y = 3(48) -12 = 144-12 = 132
132 +48 = 180
the angle is 132