a cart's initial velocity is +3.0 meters per second. What is its final velocity after accelerating at a rate of 1.5m/s2 for 8.0
1 answer:
The final velocity is +15.0 m/s
Explanation:
The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:
where
v is the velocity at time t
u is the initial velocity
a is the acceleration
t is the time
For the cart in this problem, we have:
u = +3.0 m/s (initial velocity)
(acceleration)
t = 8.0 s (time)
Substituting, we find the final velocity:
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Answer:
Explanation:
Consider another special case in which the inclined plane is vertical (θ=π/2). In this case, for what value of m1 would the acceleration of the two blocks be equal to zero
F - Force
T = Tension
m = mass
a = acceleration
g = gravitational force
Let the given Normal on block 2 = N
and
and the tension in the given string is said to be
When the acceleration
for the said block 1.
It will definite be zero only when Force is zero , F=0.
Here by Force, F
I refer net force on block 1.
Now we know
It is known that if the said
,
then Tension
,
Now making
So If we are to make Force equal to zero
