Given:
A line passes through (1,-2) and is perpendicular to 
.
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.
Slope of this line is
Product of slope of two perpendicular lines is -1.
Now, slope of required line is 
and it passes through (1,-2). So, the equation of line is
where, m is slope.
Therefore, the equation of required line is .
Answer:
11 * w
Step-by-step explanation:
"product" in math means "multiply". "The product of 11 and w" is "the multiplication of 11 and w".
Write the expression:
The Multiplication: *
11 and w: 11 * w
11 * w is your answer.
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Answer:
sorry i am in 7th grade
Step-by-step explanation:
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Let one odd integer = x
other odd integer = x +2
Sum = x + x+2 = -44
=> 2x + 2 = -44
=> 2x = -44 -2 = -46
=> x = -46/2 = -23
x+2 = -23 + 2 = -21
Integers are -23 and -21
When we draw a circle with the centre at D and have a tangent HF to the circle D at point E, the angle DEF will be a right angle.
In other words angle DEF = 90 degrees
Since HF, the tangent, is a straight line, the other angle DEH should also be = 90 degrees because the straight line has an angle of 180 degrees
Therefore angle DEF = angle DEH = 90 degrees
Therefore, angle DEF is congruent to angle DEH (Option A)
