Answer:
64k^2 - 16k +1
Step-by-step explanation:
We can rewrite this as
(-8k+1) ^2
We know that (a+b)^2 = a^2 +2ab +b^2
Let a = -8k and b = 1
(-8k+1) = (-8k)^2 +2*(-8k)(1) + 1^2
=64k^2 - 16k +1
The Pythagorean theorem can be used to find the length of the diagonal (d) of a square.
d² = (3√2)² + (3√2)² = 18 + 18 = 36
d = √36 = 6
The measure of the diagonal is 6.
Answer:
-26= -9x + 10
-26 - 10= -9x
-36=-9x
-36:(-9)=x
4=x
Step-by-step explanation:
1. you pass +10 to the left in minus
2. you resolve what you've got on the left
then you pass the multiplying -9 to the left dividing