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2 years ago

Please help: 12x^4(-5/6x^3y^2) If possible, include steps Thanks.

1 answer:

4 0

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Question
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$12x^4(- \frac{5}{6} x^3y^2)$

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Multiply the constant: 12 x (-5/6)
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$-10x^4( x^3y^2)$

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Multiply the x (we add the power together when we multiply)
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$-10x^7y^2$

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Answer: -10x⁷y²
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The measure of angle P is five less than four times the measure of angle Q. Of angle P and angle Q are supplementary angles, fin

Andru [333]

Answer:

m∠P=140°

Step-by-step explanation:

Given:

∠P and ∠Q are supplementary angles.

The measure of angle P is five less than four times the measure of angle Q.

To find m∠P

Solution:

The measure of angle P can be given as:

A) $m\angle P=4(m\angle Q-5)$

And

B) $m\angle P+ m\angle Q=180$ [Definition of supplementary angles]

Substituting equation A into B.

$4(m\angle Q-5)+ m\angle Q=180$

Solving for $m\angle Q$

Using distribution:

$4m\angle Q-20+ m\angle Q=180$

Simplifying by combining like terms.

$5m\angle Q-20=180$

Adding 20 to both sides.

$5m\angle Q-20+20=180+20$

$5m\angle Q=200$

Dividing both sides by 5.

$\frac{5m\angle Q}{5}=\frac{200}{5}$

$m\angle Q=40$

Substituting $m\angle Q=40$ in equation B.

$m\angle P+ 40=180$

Subtracting both sides by 40.

$m\angle P+ 40-40=180-40$

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Thus, we have:

m∠P=140° (Answer)

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$g(x) = 10^{x+4}$

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In the image you can see what's mean sum a constant in the $x$ of a function.

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