2cos^2 x + 3sin x = 0
2(1 - sin^2 x) + 3sin x = 0
2 - 2sin^2 x + 3sin x = 0
2sin^2 x - 3sin x - 2 = 0
Let sin x = m, then
2m^2 - 3m - 2 = 0
2m^2 + m - 4m - 2 = 0
m(2m + 1) - 2(2m + 1) = 0
(m - 2)(2m + 1) = 0
m = 2 or m = -1/2
Now, sin x = -1/2
Therefore, x = 1/6(12nπ - π) and 1/6(12nπ + 7π)
Answer:
Check the explanation
Step-by-step explanation:
Let and be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume having with mean and having mean
Also we have given the variance is constant
A)
We can test hypothesis as
For this problem
Test statistic is
Where
We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.
Answer:
one because it is cilinder
Answer:
Comparing each pair of lines,
AB and EF,
BC and FG,
CD and GH,
DA and HE.
For, AB and EF,
If we take a look at both the lines they are the mirror image of each other, the distance between point A and B is 1 unit upwards, and 2 unit sidewise, similarly between point E and F the distance is 1 unit upwards, and 2 unit sidewise. therefore, the length of both the lines is the same.
Also, we can use the formula, for the distance between two points on a coordinate plane,
,
As we can see in the image,
A = (-1, 1),
B = (-3, 2),
C = (-4, 4),
D = (-2, 6),
E = (2, 0),
F = (4, 1),
G = (5, 3),
H = (3, 5),
Solving using the formula,
AB = EF = √5,
BC = FG = √5,
CD = GH = √8,
DA = HE = √26,
Therefore, the length of all the sides of the polygon are the same,
Hence, the two figures are congruent.
Step-by-step explanation: