Formula: Ca=Vt^2/r
centripetal acceleration(Ca)= ?
tangential speed(Vt)= 2.8m/s
Radius(r)=2m
Substitute: Ca=2.8^2/2
Ca=3.92m/s^2
Answer:
73.6 minutes
Explanation:
relative time = time interval / √(1 - observer velocity² / speed of light²)
we have relative time. we want time interval.
rearrange
time interval = relative time x √(1 - observer velocity² / speed of light²)
convert 85 mins into seconds
85 x 60 = 5100
1.5 x 10⁸ as a number is 150000000
for c = 299 792 458
time interval = 5100 x √(1 - 150 000 000² / 299 792 458²)
for c = 3 x 10⁸
time interval = 5100 x √(1 - 150 000 000² / 300 000 000²)
time interval = 5100 x 0.866
time interval = 4415.71
divide by 60 for back into minutes
time = 73.6 minutes
Answer:
At its most natural frequency. ... A forceful voice, exquisite control of frequency, and oscillating
Explanation:
Formula for angle subtended at the center of the circular arc is as follows.
where, S = length of the rod
r = radius
Putting the given values into the above formula as follows.
=
=
=
Now, we will calculate the charge density as follows.
=
=
Now, at the center of arc we will calculate the electric field as follows.
E =
=
= 34.08 N/C
Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.
We can solve the problem by using Newton's second law of motion:
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object
In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>
B) 1.4 m/s2 horizontally.</span>